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fix: Let last name empty if username doesn't have one
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7070a0e51f
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@ -4,9 +4,13 @@ const spamwatchMiddleware = require('../plugins/lib-spamwatch/Middleware.js')(is
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async function getUserInfo(ctx) {
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async function getUserInfo(ctx) {
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const Strings = getStrings(ctx.from.language_code);
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const Strings = getStrings(ctx.from.language_code);
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let lastName = ctx.from.last_name;
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if (lastName === undefined) {
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lastName = " ";
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}
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userInfo = Strings.userInfo
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userInfo = Strings.userInfo
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.replace('{userName}', `${ctx.from.first_name} ${ctx.from.last_name}` || Strings.unKnown)
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.replace('{userName}', `${ctx.from.first_name} ${lastName}` || Strings.unKnown)
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.replace('{userId}', ctx.from.id || Strings.unKnown)
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.replace('{userId}', ctx.from.id || Strings.unKnown)
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.replace('{userHandle}', ctx.from.username ? `@${ctx.from.username}` : Strings.varNone)
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.replace('{userHandle}', ctx.from.username ? `@${ctx.from.username}` : Strings.varNone)
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.replace('{userPremium}', ctx.from.is_premium ? Strings.varYes : Strings.varNo)
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.replace('{userPremium}', ctx.from.is_premium ? Strings.varYes : Strings.varNo)
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